Dodgers force World Series to decisive Game 7 by holding off Blue Jays 3-1

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Los Angeles Dodgers pitcher Yoshinobu Yamamoto gestures during the fourth inning in Game 6 of baseball's World Series against the Toronto Blue Jays, on Friday in Toronto.

Los Angeles Dodgers pitcher Yoshinobu Yamamoto gestures during the fourth inning in Game 6 of baseball's World Series against the Toronto Blue Jays, on Friday in Toronto. Brynn Anderson/AP hide caption

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Brynn Anderson/AP

TORONTO — Yoshinobu Yamamoto beat Toronto for the second time in a week, slumping Mookie Betts hit a two-run single in a three-run third inning and the defending champion Los Angeles Dodgers held off the Blue Jays 3-1 on Friday night to force the World Series to a decisive Game 7.

Yamamoto was not quite as sharp as in his Game 2 four-hitter, the first World Series complete game in a decade. He lasted six innings and allowed only a third-inning RBI single by George Springer, who returned after missing two games with an injury to his right side.

Rookie relievers Justin Wrobleski and Roki Sasaki combined for six outs before starter Tyler Glasnow came out of the bullpen to escape a ninth-inning jam and rescue the Dodgers.

Glasnow needed only three pitches to do it. With runners on second and third, he got Ernie Clement to pop up his first delivery on the infield for the first out. Andrés Giménez then hit a line drive to left field that Kiké Hernández turned into a game-ending double play.

Hernández caught the ball on the run in shallow left-center and fired to second base, where Miguel Rojas made a tough pick of a one-hop throw to double off Addison Barger.

Max Scherzer will start Game 7 on Saturday night for the Blue Jays. He also started the last World Series Game 7, getting a no-decision when Washington won the 2019 title over Houston.

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